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595721-1G
(R)-(+)-3,3'-Dibromo-1,1'-bi-2-naphthol (C15-1205-050)
Price: $641.66List Price: $712.95Application ( R )-(+)-3,3′-Dibromo-1,1′-bi-2-naphthol reacts with zirconium(IV) tert -butoxide to form a chiral zirconium complex, which can efficiently catalyze: anti -selective catalytic asymmetric aldol reactions of silyl enol ethers -
595721-250MG
(R)-(+)-3,3'-Dibromo-1,1'-bi-2-naphthol (C15-1205-051)
Price: $205.61List Price: $228.45Application ( R )-(+)-3,3′-Dibromo-1,1′-bi-2-naphthol reacts with zirconium(IV) tert -butoxide to form a chiral zirconium complex, which can efficiently catalyze: anti -selective catalytic asymmetric aldol reactions of silyl enol ethers -
700673-100MG
(R)-3,3'-Di-9-phenanthrenyl-1,1'-bi-2-naphthol (C15-1307-832)
Price: $307.39List Price: $341.55(R)-3,3'-Di-9-phenanthrenyl-1,1'-bi-2-naphthol -
690007-100MG
(S)-3,3'-Bis(2,4,6-triisopropylphenyl)-1,1'-bi-2-naphthol
Price: $238.18List Price: $264.64Application ( S )-3,3′-Bis(2,4,6-triisopropylphenyl)-1,1′-bi-2-naphthol can be used as a reactant to prepare BINOL-based chiral N -triflyl thiophosphoramides as chiral Bronsted acid catalysts for the asymmetric synthesis of -
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33420-100G-R
1-Naphthol (C15-1291-277)
Price: $476.41List Price: $529.35Packaging bottled under inert gas -
33420-250G-R
1-Naphthol (C15-1291-278)
Price: $985.71List Price: $1,095.24Packaging bottled under inert gas -
491454-250MG
2-Naphthol-1,3,4,5,6,7,8-d7
Price: $588.00List Price: $653.33Packaging This product may be available from bulk stock and can be packaged on demand. For information on pricing, availability and packaging, please contact Stable Isotopes Customer Service . -
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HPA040154-25UL
ANTI-SCEL
Price: $540.00List Price: $600.00Immunogen sciellin recombinant protein epitope signature tag (PrEST) Application All Prestige Antibodies Powered by Atlas Antibodies are developed and validated by the Human Protein Atlas (HPA) project and as a result, are supported by the most -
44802
HYDROXY NAPHTHOL BLUE, 100 G
Price: $243.53List Price: $270.58C<sub>20</sub>H<sub>12</sub>N<sub>2</sub>O<sub>11</sub>S<sub>3</sub>Na<sub>2</sub>